electromagnetic-inductionWHERE cd.courseId=3 AND cd.subId=8 AND chapterSlug='electromagnetic-induction' and status=1SELECT ex_no,page_number,question,question_no,id,chapter,solution FROM question_mgmt as q WHERE courseId='3' AND subId='8' AND chapterId='120' AND ex_no!=0 AND status=1 ORDER BY ex_no,CAST(question_no AS UNSIGNED) CBSE Class 12 Free NCERT Book Solution for Physics

Notice: Undefined variable: page_banner in /var/www/html/saralstudy/ss_new/web/chapter.php on line 120

Chapter 6 : Electromagnetic Induction


In the sixth chapter of Physics NCERT Class 12, you get to learn about electromagnetic induction. This chapter contains a bit of the previous chapter’s information about magnetism and matter too. The chapter comprises ten topics in total, and teach you about the concept of magnetic induction, magnetic flux, inductance, eddy currents and a lot more. You will also get to learn about Faraday’s Law of electromagnetic induction, Fleming’s Right Hand Rule, and Lenz’s Law in this chapter.

Exercise 1
Q:
A:

Length of the rectangular wire, l = 8 cm = 0.08 m

Width of the rectangular wire, b = 2 cm = 0.02 m

Hence, area of the rectangular loop,

A = lb

= 0.08 × 0.02

= 16 × 10−4 m2

Magnetic field strength, B = 0.3 T

Velocity of the loop, v = 1 cm/s = 0.01 m/s

(a) Emf developed in the loop is given as:

e = Blv

= 0.3 × 0.08 × 0.01 = 2.4 × 10−4 V

Time taken to travel along the width , t = Distance traveled / Velocity = b / v

                                                                    =  0.02 / 0.01 = 2 s

Hence, the induced voltage is 2.4 × 10−4 V which lasts for 2 s.

(b) Emf developed, e = Bbv

= 0.3 × 0.02 × 0.01 = 0.6 × 10−4 V

Time taken to travel along the length, t = Distance traveled / Velocity = l / v
                                                                     =  0.08 / 0.01 = 8 s

Hence, the induced voltage is 0.6 × 10−4 V which lasts for 8 s.