NCERT Solution
Class 11
Chemistry
Chemical Bonding and Molecular Structure
draw diagrams showing the formation of a double bo...

Question:
Draw diagrams showing the formation of a double bond and a triple bond between carbon atoms in C₂H₄ and C₂H₂ molecules.

Answer:

C2H4 :

The electronic configuration of C-atom in the excited state is:

C has 4 unpaired electrons in the valence shell,therefore in the formation of C₂H₄ , each Carbon atom undergoes sp² hybridization leaving 2pz orbital unhybridized.

One sp² hybrid orbital of one carbon overlaps with sp² hybrid orbital of other carbon atom to form sigma c---c bond.Now the unhybridized 2pz orbital of one carbon atom overlaps sidewise with similar orbital of the other carbon atom to form pie bond.The remaining 2 sp² hybrid orbitals of both carbon atoms overlap axially with the half filled 1s orbitals of hydrogen atom forming C---H sigma bond

ORBITAL STRUCTURE OF C₂H₄

C₂H₂ :

Here both the carbon atoms undergoes sp hybridization leaving 2 unhybridized (2py & 2pz) orbitals.One sp hybrid orbital of one carbon atom overlaps axially with sp hybrid orbital of other carbon forming C----C sigma bond. The two unhybridised orbital of one carbon overlaps sidewise with similar orbital of other carbon atom to form two pie bonds. The remaining hybrid orbitals of each carbon overlaps axially with half filled orbitals of Hydrogen forming sigma bond.

ORBITAL PICTURE OF C₂H₂

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Question:
Draw diagrams showing the formation of a double bond and a triple bond between carbon atoms in C₂H₄ and C₂H₂ molecules.

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Question: Draw diagrams showing the formation of a double bond and a triple bond between carbon atoms in C2H4 and C2H2 molecules.

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Question:
Draw diagrams showing the formation of a double bond and a triple bond between carbon atoms in C₂H₄ and C₂H₂ molecules.