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Some Basic Concepts of Chemistry
dinitrogen and dihydrogen react with each other to...

Question:
Dinitrogen and dihydrogen react with each other to produce ammonia according to the following chemical equation:

N2(g) + H2(g) → 2NH3(g)

(i) Calculate the mass of ammonia produced if 2.00 × 103 g dinitrogen reacts with 1.00 × 103 g of dihydrogen.

(ii) Will any of the two reactants remain unreacted?

(iii) If yes, which one and what would be its mass?

Answer:

(i) Balancing the given chemical equation,

Total mass of Ammonia = 2((14) +3(1))= 34 g

From the chemical equation,we can write

28gm of N₂ reacts with 6gm of H₂ to produce ammonia= 34g

Or 1 gm of N₂ reacts with 1gm of H₂ to produce ammonia= 34/28*1

Or when 2.00x10³ g of N₂ reacts with 1.00x10³ gm of H₂ to produce ammonia

=34/28 *2.00x10³=2428.57g

hence 2.00 × 10³ g of dinitrogen will react with 1.00x10³ g of dihydrogen to give 2428.57 g of ammonia

Given, Amount of dihydrogen = 1.00 × 10³ g

Hence, N₂ is the limiting reagent.

(ii) N₂ is the limiting reagent and H₂ is the excess reagent. Hence, H₂ will remain unreacted.

(iii) Mass of dihydrogen left unreacted = 1.00 × 10³ g – 428.6 g

= 571.4 g

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