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Class 11
Chemistry
Chemical Bonding and Molecular Structure
compare the relative stability of the following sp...

Question:
Compare the relative stability of the following species and indicate their magnetic properties:

O₂,O₂⁺,O₂^- (superoxide), O₂^2-(peroxide)

Answer:

The stability of following species can be decided on the basis of bond order as follows:

O2 : KK

Bond order =1/2(N_b-N_a)

= 1/2(8-4)

= 2 = Paramagnetic

Similarly, the electronic configuration of O₂⁺can be written as:

Bond order of O₂⁺= 1/2(8-3)

= 2.5 = paramagnetic

Electronic configuration of O₂^- ion will be:

Bond order of = 1/2(8-5)

= 1.5 = paramagnetic

Electronic configuration of O₂^2- ion will be:

Bond order of O₂^2- =1/2(8-6) = 1 diamagnetic

The larger the bond order,greater is the stability

Therefore the stability decreases as O₂⁺> O₂ > O₂^- > O₂^2-.

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Question:
Compare the relative stability of the following species and indicate their magnetic properties:

O₂,O₂⁺,O₂^- (superoxide), O₂^2-(peroxide)

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Question: Compare the relative stability of the following species and indicate their magnetic properties: O2,O2+,O2- (superoxide), O22-(peroxide)

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Question:
Compare the relative stability of the following species and indicate their magnetic properties:

O₂,O₂⁺,O₂^- (superoxide), O₂^2-(peroxide)