SELECT * FROM question_mgmt as q WHERE id=1358 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=2 AND subId=9 AND chapterId=45 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED) CBSE Free NCERT Solution of 11th chemistry Chemical Bonding and Molecular Structure what is meant by the term bond order calculate th

Question:

What is meant by the term bond order? Calculate the bond order of: N2, O2,O2+,and O2-.

Answer:

Bond order is defined as the number of covalent bonds in a covalent molecule. It is equal to one half of the difference between the number of electrons in the bonding and antibonding molecular orbitals.

Bond order = [no of electrons in bonding MO – no of electrons in antibonding MO] / 2

BOND ORDER OF N2

Electronic configuration of N

Number of bonding electrons = 10

Number of anti-bonding electrons = 4

Bond order of nitrogen molecule = 1/2 (10-4) = 3

 

Bond order of O2

Electronic configuration of O

Number of bonding electrons = 8

Number of anti-bonding electrons = 4 

Bond order = 1/2 (8-4) =2

Hence, the bond order of oxygen molecule is 2.

 

Bond order of O2+

Electronic configuration of can be written as:

Bond order of O2+=1/2 (8-3)= 2.5

Thus, the bond order of  O2+ is 2.5.

 

Bond order of O2-

The electronic configuration of O2-  ion will be:

Bond order of = O2- =1/2 (8-5) = 1.5

Thus, the bond order of ion is  O2- = 1.5.


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