SELECT * FROM question_mgmt as q WHERE id=3025 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=2 AND subId=9 AND chapterId=48 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED)

Question:

One mole of H2O and one mole of CO are taken in 10 L vessel and heated to 725 K. At equilibrium 40% of water (by mass) reacts with CO according to the equation,

H2O (g) + CO (g) ↔  H2 (g) + CO2 (g)

Calculate the equilibrium constant for the reaction.

Answer:

The given reaction is:

                                  H2O (g)   +  CO (g)  ↔   H2 (g)  +  CO2 (g)

Initial Concentration:     1/10 M       1/10 M           0              0

At equilibrium              1-0.4/10 M  1-0.4/10 M  0.4/10M 0.4/10M

                                = 0.06M       0.06M         0.04M     0.04M

Therefore, the equilibrium constant for the reaction,

 


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