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Class 11
Chemistry
Equilibrium
one mole of h2o and one mole of co are taken in 10...

Question:
One mole of H₂O and one mole of CO are taken in 10 L vessel and heated to 725 K. At equilibrium 40% of water (by mass) reacts with CO according to the equation,

H₂O (g) + CO (g) ↔ H₂ (g) + CO₂ (g)

Calculate the equilibrium constant for the reaction.

Answer:

The given reaction is:

H₂O (g) + CO (g) ↔ H₂ (g) + CO₂ (g)

Initial Concentration: 1/10 M 1/10 M 0 0

At equilibrium 1-0.4/10 M 1-0.4/10 M 0.4/10M 0.4/10M

= 0.06M 0.06M 0.04M 0.04M

Therefore, the equilibrium constant for the reaction,

1
0
0
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Question:
One mole of H₂O and one mole of CO are taken in 10 L vessel and heated to 725 K. At equilibrium 40% of water (by mass) reacts with CO according to the equation,

H₂O (g) + CO (g) ↔ H₂ (g) + CO₂ (g)

Calculate the equilibrium constant for the reaction.

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Question: One mole of H2O and one mole of CO are taken in 10 L vessel and heated to 725 K. At equilibrium 40% of water (by mass) reacts with CO according to the equation, H2O (g) + CO (g) ↔ H2 (g) + CO2 (g) Calculate the equilibrium constant for the reaction.

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Question:
One mole of H₂O and one mole of CO are taken in 10 L vessel and heated to 725 K. At equilibrium 40% of water (by mass) reacts with CO according to the equation,

H₂O (g) + CO (g) ↔ H₂ (g) + CO₂ (g)

Calculate the equilibrium constant for the reaction.