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Question:

What is the equilibrium concentration of each of the substances in the equilibrium when the initial concentration of ICl was 0.78 M ?

2ICl (g)  ↔  I2 (g) + Cl2 (g);     Kc = 0.14

Answer:

The given reaction is:
                                 2ICl (g)  ↔  I2 (g) + Cl2 (g)
Initial conc.                0.78 M           0           0
At equilibrium         (0.78 - 2x) M     x M        x M

Now we can write, Kc  =  I2  x Cl2   /  (ICl)2  


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