SELECT * FROM question_mgmt as q WHERE id=3215 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=2 AND subId=9 AND chapterId=50 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED) CBSE Free NCERT Solution of 11th chemistry Hydrogen discuss the principle and method of softening of h

Question:

Discuss the principle and method of softening of hard water by synthetic ion-exchange resins.

Answer:

The process of treating permanent hardness of water using synthetic resins is based on the exchange of cations (e.g., Na+, Ca2+, Mg2+ etc) and anions (e.g., Cl-, SO2-4, HCO-3 etc) present in water by H+ and OH- ions respectively.

Synthetic resins are of two types:

1) Cation exchange resins

2) Anion exchange resins

Cation exchange resins are large organic molecules that contain the -SO3H group. The resin is firstly changed to RNa (from RSO3H) by treating it with NaCl. This resin then exchanges Na+ ions with Ca2+ and Mg2+ ions, thereby making the water soft.

2RNa   +   M2+ (aq)  →  R2M(s) +  2Na + (aq)

There are cation exchange resins in H+ form. The resins exchange H+ ions for Na+, Ca2+, and Mg2+ ions.

Anion exchange resins exchange OH- ions for anions like Cl-,HCO-3, and SO42- present in water.

During the complete process, water first passes through the cation exchange process. The water obtained after this process is free from mineral cations and is acidic in nature.

This acidic water is then passed through the anion exchange process where OH- ions neutralize the H+ ions and de-ionize the water obtained.


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