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in the estimation of sulphur by carius method 0 4...

Question:
In the estimation of sulphur by Carius method, 0.468 g of an organic sulphur compound afforded 0.668 g of barium sulphate. Find out the percentage of sulphur in the given compound.

Answer:

Total mass of organic compound = 0.468 g [Given]

Mass of barium sulphate formed = 0.668 g [Given]

1 mol of BaSO₄ = 233 g of BaSO₄ = 32 g of sulphur

Thus, 0.668 g of BaSO₄ contains 32x0.668/233 g of sulphur = 0.0917 g of sulphur

Therefore, percentage of sulphur = 0.0197/0.468 x100 = 19.59 %

Hence, the percentage of sulphur in the given compound is 19.59 %.

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Question:
In the estimation of sulphur by Carius method, 0.468 g of an organic sulphur compound afforded 0.668 g of barium sulphate. Find out the percentage of sulphur in the given compound.

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Question: In the estimation of sulphur by Carius method, 0.468 g of an organic sulphur compound afforded 0.668 g of barium sulphate. Find out the percentage of sulphur in the given compound.

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Question:
In the estimation of sulphur by Carius method, 0.468 g of an organic sulphur compound afforded 0.668 g of barium sulphate. Find out the percentage of sulphur in the given compound.