SELECT * FROM question_mgmt as q WHERE id=3241 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=2 AND subId=9 AND chapterId=49 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED)

Question:

Why does the following reaction occur ?

XeO4– 6(aq)  +  2F – (aq) + 6H + (aq)  →   XeO3(g)  +  F2(g) + 3H2O(l)

What conclusion about the compound Na4XeO6 (of which XeO4– 6 is a part) can be drawn from the reaction.

Answer:

The given reaction occurs because XeO4– 6 oxidises F- and F- reduces XeO4-6.

In this reaction, the oxidation number (O.N.) of Xe decreases from +8 in XeO4– 6 to +6 in XeO3 and the O.N. of F increases from -1 in F- to O in F2.

Hence, we can conclude that is a stronger oxidising agent than F-.


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