Question:
Why does the following reaction occur ?

XeO^4– _6(aq)+ 2F^– _(aq) + 6H⁺_(aq)→ XeO_3(g) + F_2(g) + 3H₂O_(l)

What conclusion about the compound Na₄XeO₆ (of which XeO^4– 6 is a part) can be drawn from the reaction.

Answer:

The given reaction occurs because XeO^4– 6 oxidises F^- and F^- reduces XeO^4-₆.

In this reaction, the oxidation number (O.N.) of Xe decreases from +8 in XeO^4– 6 to +6 in XeO₃ and the O.N. of F increases from -1 in F^- to O in F₂.

Hence, we can conclude that is a stronger oxidising agent than F^-.

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Question:
Why does the following reaction occur ?

XeO^4– _6(aq)+ 2F^– _(aq) + 6H⁺_(aq)→ XeO_3(g) + F_2(g) + 3H₂O_(l)

What conclusion about the compound Na₄XeO₆ (of which XeO^4– 6 is a part) can be drawn from the reaction.

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Question: Why does the following reaction occur ? XeO4– 6(aq) + 2F – (aq) + 6H + (aq) → XeO3(g) + F2(g) + 3H2O(l) What conclusion about the compound Na4XeO6 (of which XeO4– 6 is a part) can be drawn from the reaction.

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Question:
Why does the following reaction occur ?

XeO^4– _6(aq)+ 2F^– _(aq) + 6H⁺_(aq)→ XeO_3(g) + F_2(g) + 3H₂O_(l)

What conclusion about the compound Na₄XeO₆ (of which XeO^4– 6 is a part) can be drawn from the reaction.