Question:
Consider the reactions:

(a) 6CO_2(g) + 6H₂O_(l) → C₆H₁₂O_6(aq) + 6O_2(g)

(b) O_3(g)+ H₂O_2(l) → H₂O_(l)+ 2O_2(g)

Why it is more appropriate to write these reactions as:

(a) 6CO_2(g) + 12H₂O_(l) → C₆H₁₂O_6(aq) + 6H₂O_(l)+ 6O_2(g)

(b) O_3(g) + H₂O_2(l) → H₂O_(l)+ O_2(g) + O_2(g)

Also suggest a technique to investigate the path of the above (a) and (b) redox reactions.

Answer:

(a) The process of photosynthesis involves two steps.

Step 1:

H₂O decomposes to give H₂ and O₂.

2H₂O_(l) → 2H_2(g) + O_2(g)

Step 2:

The H₂ produced in step 1 reduces CO₂, thereby producing glucose (C₆H₁₂O₆) and H₂O.

6CO_2(g) + 12H_2(g) → C₆H₁₂O_6(s) + 6H₂O_(l)

Now, the net reaction of the process is given as:

It is more appropriate to write the reaction as given above because water molecules are also produced in the process of photosynthesis.

The path of this reaction can be investigated by using radioactive H₂O¹⁸in place of H₂O.

(b) O₂ is produced from each of the two reactants O₃and H₂O₂. For this reason, O₂is written twice.

The given reaction involves two steps. First, O₃ decomposes to form O₂ and O. In the second step, H₂O₂ reacts with the O produced in the first step, thereby producing H₂O and O₂.

The path of this reaction can be investigated by using H₂O¹⁸or O¹⁸₃.

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