SELECT * FROM question_mgmt as q WHERE id=1228 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=2 AND subId=9 AND chapterId=42 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED) CBSE Free NCERT Solution of 11th chemistry Some Basic Concepts of Chemistry calculate the mass of sodium acetate ch3coona re

Question:

Calculate the mass of sodium acetate (CH3COONa) required to make 500 mL of 0.375 molar aqueous solution. Molar mass of sodium acetate is 82.0245 g mol–1

Answer:

0.375 M solution of (CH3COONa) = 0.375 moles(grams) of (CH3COONa) dissolved in 1000 ml of solvent.

 

But according to question ,we have to make a 500 ml solution of (CH3COONa)

 

∴Number of moles of sodium acetate in 500 mL

 

 

Molar mass of sodium acetate = 82.0245 g mole–1 (Given)

 

∴ Required mass of sodium acetate = (82.0245 g mol–1) (0.1875 mole)

 

= 15.38 g

 

 


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