SELECT * FROM question_mgmt as q WHERE id=1232 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=2 AND subId=9 AND chapterId=42 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED)

Question:

Calculate the atomic mass (average) of chlorine using the following data:

  % Natural Abundance Molar Mass
35Cl 75.77 34.9689
37Cl 24.23 36.9659

 

Answer:

Atomic mass of first isotope = 34.9689

 

Natural abundance of first isotope = 75.77% or 0.757

 

Atomic mass of second isotope= 36.9659

 

Natural abundance of second isotope= 24.23% or 0.242

 

Now average atomic mass of chlorine

 

= [34.9689x 0.757 + 36.9659x 0.242]/(0.757+0.242) =35.4521

 

So, the average atomic mass of chlorine = 35.4527 u

 


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