SELECT * FROM question_mgmt as q WHERE id=1234 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=2 AND subId=9 AND chapterId=42 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED)

Question:

If the density of methanol is 0.793 kg L–1, what is its volume needed for making 2.5 L of its 0.25 M solution?

Answer:

Let the volume of 0.25 M of ethanol needed = x Molar mass of methanol (CH3OH) = (1 × 12) + (4 × 1) + (1 × 16) = 32 g mol–1 = 0.032 kg mol–1

 

Molarity of methanol solution 

= 24.78 mol L–1 (Since density is mass per unit volume)

Applying, M1V1 = M2V2

(Given solution) (Solution to be prepared)

(24.78 mol L–1) x = (2.5 L) (0.25 mol L–1)

x = 0.0252 L

x = 25.22 mL

 

 


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