SELECT * FROM question_mgmt as q WHERE id=1240 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=2 AND subId=9 AND chapterId=42 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED)
How are 0.50 mol Na2CO3 and 0.50 M Na2CO3 different?
Molar mass of Na2CO3 = (2 × 23) + 12.00 + (3× 16) = 106 g mol–1
1 mole of Na2CO3 = 106 g
0.5 mol of Na2CO3 = 53 g Na2CO3
⇒ 0.50 M of Na2CO3 = 0.50 mol/L Na2CO3
Hence, 0.50 mol of Na2CO3 is present in 1 L of water or 53 g of Na2CO3 is present in 1 L of water.
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