SELECT * FROM question_mgmt as q WHERE id=185 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=2 AND subId=9 AND chapterId=42 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED) CBSE Free NCERT Solution of 11th chemistry Some Basic Concepts of Chemistry if the speed of light is 3 0 times 108 ms ndash

Question:

If the speed of light is 3.0 × 108 ms–1, calculate the distance covered by light in 2.00 ns.

Answer:

According to the question:

Time taken to cover the distance = 2.00 ns

= 2.00 × 10–9 s

Speed of light = 3.0 × 108 ms–1

We know speed = distance/time

Or distance = speed x time

Therefore   Distance travelled by light in 2.00 ns

= Speed of light × Time taken

= (3.0 × 108 ms –1) (2.00 × 10–9 s)

= 6.00 × 10–1 m

= 0.600 m


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