SELECT * FROM question_mgmt as q WHERE id=1284 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=2 AND subId=9 AND chapterId=43 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED)

Question:

If the diameter of a carbon atom is 0.15 nm, calculate the number of carbon atoms which can be placed side by side in a straight line across length of scale of length 20 cm long.

Answer:

Diameter of carbon atom = 0.15nm = 0.15 x 10-9m = 1.5 x 10-10m

Length along which atoms are to be placed = 20cm = 20x10-2m = 2 x 10-1m

Therefore no of carbon atoms which can be placed along the length

= (2 x 10-1m) / (1.5x10-10 )

=1.33x109


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