SELECT * FROM question_mgmt as q WHERE id=1286 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=2 AND subId=9 AND chapterId=43 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED)

Question:

The diameter of zinc atom is 2.6 Å .

Calculate

(a) radius of zinc atom in pm and

(b) number of atoms present in a length of 1.6 cm if the zinc atoms are arranged side by side lengthwise.

Answer:

(a) radius = 2.6/2 = 1.3Å = 1.3 x 10-10m = 130pm

(b) given Length of the arrangement

= 1.6 cm = 1.6 × 10–2 m

Diameter of zinc atom = 2.6 × 10–10 m

∴ Number of zinc atoms present in the arrangement


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