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Question:

Neon gas is generally used in the sign boards. If it emits strongly at 616 nm, calculate

(a) the frequency of emission,

(b) distance traveled by this radiation in 30 s

(c) energy of quantum and

(d) number of quanta present if it produces 2 J of energy.

Answer:

λ = 616nm  or = 616x10-9m

a) Frequency , v=c/ λ = 3.8x108 / 616x10-9 = 4.87x1014 s-1

b) Velocity of the radiation = 3x108 m/s

Therefore distance travelled in 30s = 30x3x108 = 9.0x109m

c) E = hv = hc/ λ = (6.626x10-34)(3.0x108) / (616x10-9 ) = 32.27x10-20J

d) No of quanta in 2J of energy = 2/32.27 x 10-28 = 6.2x1018


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