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Question:
The longest wavelength doublet absorption transition is observed at 589 and 589.6 nm. Calculate the frequency of each transition and energy difference between two excited states.

Answer:

λ₁ = 589 nm = 5.89X10^-9m

therefore v₁=c/ λ₁ = 3x10⁸/589x10^-9 = 5.093x10¹⁴/sec

λ₂ = 589.6nm = 589.6x10^-9m

therefore v₂ = c/ λ₂ = 3x10⁸/589.6x10^-9

= 5.088x10¹⁴/sec

ΔE=E₂-E₁= h(v₂-v₁)

= (6.626x10^-34)(5.093x-5.088)x10¹⁴

= 3.31x10^-22J

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Question:
The longest wavelength doublet absorption transition is observed at 589 and 589.6 nm. Calculate the frequency of each transition and energy difference between two excited states.

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Question: The longest wavelength doublet absorption transition is observed at 589 and 589.6 nm. Calculate the frequency of each transition and energy difference between two excited states.

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Question:
The longest wavelength doublet absorption transition is observed at 589 and 589.6 nm. Calculate the frequency of each transition and energy difference between two excited states.