SELECT * FROM question_mgmt as q WHERE id=1302 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=2 AND subId=9 AND chapterId=43 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED)

Question:

The ejection of the photoelectron from the silver metal in the photoelectric effect experiment can be stopped by applying the voltage of 0.35 V when the radiation 256.7 nm is used. Calculate the work function for silver metal.

Answer:

From the principle of conservation of energy, the energy of an incident photon (E) is equal to the sum of the work function (W0) of radiation and its kinetic energy (K.E) i.e.,

 

Energy of incident radiation(E)= hc/λ = (6.626x10-34)(3x108)/(256.7x 10-9)

= 7.74x10-19 J

 

Since the potential applied gives the kinetic energy to the radiation ,therefore K.E of the electron = 0.35Ev

 

Therefore work function = 4.83 – 0.35 = 4.48 eV


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