SELECT * FROM question_mgmt as q WHERE id=1757 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=3 AND subId=9 AND chapterId=56 and ex_no='2' AND status=1 ORDER BY CAST(question_no AS UNSIGNED) CBSE Free NCERT Solution of 12th chemistry The Solid State if nacl is doped with 10 3mol of srcl2 what is

Question:

If NaCl is doped with 10-3mol % of SrCl2, what is the concentration of cation vacancies?

Answer:

1 Cation of Sr2+ will create 1 cation vacancy in Nacl.Therefore the number of cation vacancies created in the lattice of Nacl is equal to the number of divalent Sr2+ ions added.

Now the concentration of cation vacancy on being doped with 10-3 mol% of Srcl2.

= 10-3 mol% = 10-3 / 100 = 10-5 mol\

Also number of Sr2+ ion in 10-5 mol = 10-5 x 6.023 x 1023 = 6.023 x 1018

Therefore number of cation vacancies = 6.023 x 1018


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