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calculate the mole fraction of benzene in solution...

Question:
Calculate the mole fraction of benzene in solution containing 30% by mass in carbon tetrachloride.

Answer:

Let the total mass of the solution be 100 g and the mass of benzene be 30 g.

∴ Mass of carbon tetrachloride = (100 - 30) g = 70 g

Molar mass of benzene (C₆H₆) = (6 × 12 + 6 × 1) g mol^{- 1}

= 78 g mol^{- 1}

∴ Number of moles of C₆H₆ =30/78 mol

= 0.3846 mol

Molar mass of carbon tetrachloride (CCl₄) = 1 × 12 + 4 × 35.5

= 154 g mol^{- 1}

∴ Number of moles of CCl₄ = 70/154 mol

= 0.4545 mol

Thus, the mole fraction of C₆H₆ is given as:

= 0.3846 / (0.3846 + 0.4545)

= 0.458

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Question:
Calculate the mole fraction of benzene in solution containing 30% by mass in carbon tetrachloride.

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Question:
Calculate the mole fraction of benzene in solution containing 30% by mass in carbon tetrachloride.