SELECT * FROM question_mgmt as q WHERE id=1774 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=3 AND subId=9 AND chapterId=57 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED)

Question:

Henry's law constant for CO2 in water is 1.67 x 108Pa at 298 K. Calculate the quantity of CO2in 500 mL of soda water when packed under 2.5 atm CO2 pressure at 298 K.

Answer:

It is given that:

KH = 1.67 × 108Pa

PCO2 = 2.5 atm = 2.5 × 1.01325 × 105Pa

= 2.533125 × 105Pa

 

According to Henry's law:

PCO2 = KHX

⇒ x =  PCO2 / KH

= 2.533125 × 105 / 1.67 × 108

= 0.00152

 

We can write, 

[Since, is negligible as compared to]

 

In 500 mL of soda water, the volume of water = 500 mL

[Neglecting the amount of soda present]

We can write:

500 mL of water = 500 g of water

=500 / 18 mole of water

= 27.78 mol of water

Now, nCO2 / nH2O = x

nCO2 / 27.78 = 0.00152

nCO2 = 0.042 mol

Hence, quantity of CO2 in 500 mL of soda water = (0.042 × 44) g

= 1.848 g


< Previous Question

Next Question >

SELECT ex_no,question,question_no,id,chapter FROM question_mgmt as q WHERE courseId='3' AND subId='9' AND ex_no!=0 AND status=1 and id!=1774 ORDER BY views desc, last_viewed_on desc limit 0,10

  • Popular questions of class 12 Chemistry

SELECT ex_no,question,question_no,id,chapter FROM question_mgmt as q WHERE courseId='3' AND subId='9' AND ex_no!=0 AND status=1 and id!=1774 ORDER BY last_viewed_on desc limit 0,10

  • Recently Viewed Questions of Class 12 Chemistry

Comments

  • Answered by Ekta Mehta
  • 4 months ago

Taking Screenshots on your Samsung Galaxy M31s is very easy and quick.

  • Answered by Ekta Mehta
  • 4 months ago

Taking Screenshots on your Samsung Galaxy M31s is very easy and quick.

  • Answered by Ekta Mehta
  • 4 months ago

Taking Screenshots on your Samsung Galaxy M31s is very easy and quick.

Comment(s) on this Question


Important links

Quick Links

Resources

Support