Question: \begin{align} \int sec x . \left(sec x + tan x\right) .dx \end{align}

Answer:

\begin{align} \int sec x . \left(sec x + tan x\right) .dx \end{align}

\begin{align} =\int \left(sec^2 x + sec x . tan x\right) .dx \end{align}

\begin{align} =\int sec^2 x . dx + \int sec x . tan x .dx \end{align}

\begin{align} = tan x + sec x + C \end{align}

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