SELECT * FROM question_mgmt as q WHERE id=963 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=3 AND subId=6 AND chapterId=94 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED) CBSE Free NCERT Solution of 12th mathematics Integrals sin 2x ndash 4e3x

Question: sin 2x – 4e3x

Answer:

The anti derivative of sin 2x – 4e3x is the function of x whose derivative is sin 2x – 4e3x.

It is known that,

\begin{align} \frac {d}{dx} \left(-\frac{1}{2}cos 2x  –  \frac {4}{3} e^{3x}\right) = sin2x  –  4e^{3x} \end{align} 

Therefore, the anti derivative of (sin 2x – 4e3x) is \begin{align}  \left(-\frac{1}{2}cos 2x  –  \frac {4}{3} e^{3x}\right) \end{align} 

 

 


SELECT ex_no,question,question_no,id,chapter FROM question_mgmt as q WHERE courseId='3' AND subId='6' AND ex_no!=0 AND status=1 and id!=963 ORDER BY views desc, last_viewed_on desc limit 0,10
SELECT ex_no,question,question_no,id,chapter FROM question_mgmt as q WHERE courseId='3' AND subId='6' AND ex_no!=0 AND status=1 and id!=963 ORDER BY last_viewed_on desc limit 0,10

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