SELECT * FROM question_mgmt as q WHERE id=2245 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=3 AND subId=8 AND chapterId=117 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED) CBSE Free NCERT Solution of 12th physics Current Electricity the earth 39 s surface has a negative surface cha

Question:

The earth's surface has a negative surface charge density of 10-9 C m-2. The potential difference of 400 kV between the top of the atmosphere and the surface results (due to the low conductivity of the lower atmosphere) in a current of only 1800 A over the entire globe. If there were no mechanism of sustaining atmospheric electric field, how much time (roughly) would be required to neutralise the earth's surface? (This never happens in practice because there is a mechanism to replenish electric charges, namely the continual thunderstorms and lightning in different parts of the globe). (Radius of earth = 6.37 x 106 m.)

Answer:

Surface charge density of the earth, ÃÆ’ = 10 - 9 C m - 2

Current over the entire globe, I = 1800 A

Radius of the earth, r = 6.37 × 106 m

Surface area of the earth,

A = 4πr2

= 4π × (6.37 × 106)2

= 5.09 × 1014 m2

Charge on the earth surface,

q = ÃÆ’ × A

= 10 - 9 × 5.09 × 1014

= 5.09 × 105 C

Time taken to neutralize the earth's surface = t

Current, 

 Therefore, the time taken to neutralize the earth's surface is 282.77 s.


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SELECT ex_no,question,question_no,id,chapter FROM question_mgmt as q WHERE courseId='3' AND subId='8' AND ex_no!=0 AND status=1 and id!=2245 ORDER BY last_viewed_on desc limit 0,10

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  • 4 months ago

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