SELECT * FROM question_mgmt as q WHERE id=2252 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=3 AND subId=8 AND chapterId=117 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED) CBSE Free NCERT Solution of 12th physics Current Electricity a given n resistors each of resistance r how wil

Question:

a) Given n resistors each of resistance R, how will you combine them to get the (i) maximum (ii) minimum effective resistance? What is the ratio of the maximum to minimum resistance?

(b) Given the resistances of 1 Ω , 2 Ω , 3 Ω , how will be combine them to get an equivalent resistance of (i) (11/3) Ω  (ii) (11/5) Ω , (iii) 6 Ω , (iv) (6/11) Ω ?

(c) Determine the equivalent resistance of networks shown in Figure

Answer:

(a) Total number of resistors = n

Resistance of each resistor = R

(i) When n resistors are connected in series, effective resistance Ris the maximum, given by the product nR.

Hence, maximum resistance of the combination, R1 = nR

(ii) When n resistors are connected in parallel, the effective resistance (R2) is the minimum, given by the ratio .

Hence, minimum resistance of the combination, R2

(iii) The ratio of the maximum to the minimum resistance is,

(b) The resistance of the given resistors is,

R1 = 1 Ω , R2 = 2 Ω , R3 = 3 Ω 2

Equivalent resistance, 

Consider the following combination of the resistors.

Equivalent resistance of the circuit is given by,

Equivalent resistance, 

Consider the following combination of the resistors.

Equivalent resistance of the circuit is given by,

(iii) Equivalent resistance, R' = 6 Ω 

Consider the series combination of the resistors, as shown in the given circuit.

Equivalent resistance of the circuit is given by the sum,

R' = 1 + 2 + 3 = 6 Ω 

(iv) Equivalent resistance, 

Consider the series combination of the resistors, as shown in the given circuit.

Equivalent resistance of the circuit is given by,

(c) (a) It can be observed from the given circuit that in the first small loop, two resistors of resistance 1 Ω  each are connected in series.

Hence, their equivalent resistance = (1+1) = 2 Ω 

It can also be observed that two resistors of resistance 2 Ω  each are connected in series.

Hence, their equivalent resistance = (2 + 2) = 4 Ω .

Therefore, the circuit can be redrawn as

It can be observed that 2 Ω  and 4 Ω  resistors are connected in parallel in all the four loops. Hence, equivalent resistance (R') of each loop is given by,


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