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Class 12
Physics
Dual Nature Of Radiation And Matter
the photoelectric cut off voltage in a certain exp...

Question:
The photoelectric cut-off voltage in a certain experiment is 1.5 V. What is the maximum kinetic energy of photoelectrons emitted?

Answer:

Photoelectric cut-off voltage, V₀ = 1.5 V

The maximum kinetic energy of the emitted photoelectrons is given as: K_e = eV_o

Where,

e = Charge on an electron = 1.6 × 10⁻¹⁹ C

∴ K_e = 1.6 x 10^-19 x 1.5 = 2.4 x 10^-19 J

Therefore, the maximum kinetic energy of the photoelectrons emitted in the given experiment is 2.4 × 10⁻¹⁹ J.

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Question:
The photoelectric cut-off voltage in a certain experiment is 1.5 V. What is the maximum kinetic energy of photoelectrons emitted?

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Question:
The photoelectric cut-off voltage in a certain experiment is 1.5 V. What is the maximum kinetic energy of photoelectrons emitted?