SELECT * FROM question_mgmt as q WHERE id=1109 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=3 AND subId=8 AND chapterId=115 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED)

Question:

Check that the ratio ke2/G memp is dimensionless. Look up a Table of Physical Constants and determine the value of this ratio. What does the ratio signify?

Answer:

The given ratio is

Where,

G = Gravitational constant

Its unit is N m2 kg−2.

me and mp = Masses of electron and proton.

Their unit is kg.

e = Electric charge.

Its unit is C.

∈0 = Permittivity of free space

Its unit is N m2 C−2.

Hence, the given ratio is dimensionless.

e = 1.6 × 10−19 C

G = 6.67 × 10−11 N m2 kg-2

me= 9.1 × 10−31 kg

mp = 1.66 × 10−27 kg

This is the ratio of electric force to the gravitational force between a proton and an electron, keeping distance between them constant.


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