SELECT * FROM question_mgmt as q WHERE id=2190 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=3 AND subId=8 AND chapterId=116 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED) CBSE Free NCERT Solution of 12th physics Electrostatic Potential and Capacitance in a hydrogen atom the electron and proton are bo

Question:

In a hydrogen atom, the electron and proton are bound at a distance of about 0.53 Å:

(a) Estimate the potential energy of the system in eV, taking the zero of the potential energy at infinite separation of the electron from proton.

(b) What is the minimum work required to free the electron, given that its kinetic energy in the orbit is half the magnitude of potential energy obtained in (a)?

(c) What are the answers to (a) and (b) above if the zero of potential energy is taken at 1.06 Å separation?

Answer:

The distance between electron-proton of a hydrogen atom, d = 0.53 Å

Charge on an electron, q1 = - 1.6 ×10 -19 C

Charge on a proton,     q2 = +1.6 ×10-19 C

(a) Potential at infinity is zero.

Potential energy of the system, = Potential energy at infinity - Potential energy at distance d

where,

0 is the permittivity of free space

 


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SELECT ex_no,question,question_no,id,chapter FROM question_mgmt as q WHERE courseId='3' AND subId='8' AND ex_no!=0 AND status=1 and id!=2190 ORDER BY last_viewed_on desc limit 0,10

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