SELECT * FROM question_mgmt as q WHERE id=3426 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=2 AND subId=8 AND chapterId=112 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED) CBSE Free NCERT Solution of 11th physics Kinetic Theory a metre long narrow bore held horizontally and cl

Question:

A metre long narrow bore held horizontally (and closed at one end) contains a 76 cm long mercury thread, which traps a 15 cm column of air. What happens if the tube is held vertically with the open end at the bottom?

Answer:

Length of the narrow bore, L= 1 m = 100 cm

Length of the mercury thread, l= 76 cm

Length of the air column between mercury and the closed end, la= 15 cm

Since the boreis held vertically in air with the open end at the bottom, the mercury length that occupies the air space is: 100 - (76 + 15) = 9 cm

Hence, the total length of the air column = 15 + 9 = 24 cm

Let h cm of mercury flow out as a result of atmospheric pressure.

∴Length of the air column in the bore= 24 + hcm

And, length of the mercury column = 76 - hcm

Initial pressure, P1= 76 cm of mercury

Initial volume, V1= 15 cm3

Final pressure, P2= 76 - (76 - h) = h cm of mercury

Final volume, V2= (24 + h) cm3

Temperature remains constant throughout the process.

∴P1V1= P2V2

= 76 × 15 = h (24 + h)

h2+ 24h - 1140 = 0

∴ h  =  - 24 +- underroot [(24)+ 4 x 1 x 1140]  / 2 x 1

= 23.8 cm or -47.8 cm

Height cannot be negative.

Hence, 23.8 cm of mercurywill flow out from the boreand 52.2 cm of mercury will remain in it.

The length of the air column will be 24 + 23.8 = 47.8 cm.


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SELECT ex_no,question,question_no,id,chapter FROM question_mgmt as q WHERE courseId='2' AND subId='8' AND ex_no!=0 AND status=1 and id!=3426 ORDER BY last_viewed_on desc limit 0,10

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