SELECT * FROM question_mgmt as q WHERE id=3356 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=2 AND subId=8 AND chapterId=104 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED)
A constant retarding force of 50 N is applied to a body of mass 20 kg moving initially with a speed of 15 ms–1. How long does the body take to stop?
Retarding force, F = -50 N
Mass of the body, m= 20 kg
Initial velocity of the body, u= 15 m/s
Final velocity of the body, v= 0
UsingNewton's second law of motion, the acceleration (a) produced in the body can be calculated as:
F= ma
-50 = 20 × a
∴ a = -50 / 20 = -2.5 m/s2
Usingthe first equation of motion, the time (t) taken by the body to come to rest can be calculated as:
v= u + at
∴ t = -u /a = -15 / -2.5 = 6s
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