SELECT * FROM question_mgmt as q WHERE id=3359 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=2 AND subId=8 AND chapterId=104 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED)
The driver of a three-wheeler moving with a speed of 36 km/h sees a child standing in the middle of the road and brings his vehicle to rest in 4.0 s just in time to save the child. What is the average retarding force on the vehicle? The mass of the three-wheeler is 400 kg and the mass of the driver is 65 kg.
Initial speed of the three-wheeler, u = 36 km/h = 10 m/s
Final speed of the three-wheeler, v = 0 m/s
Time, t = 4 s Mass of the three-wheeler, m = 400 kg
Mass of the driver, m' = 65 kg
Total mass of the system, M = 400 + 65 = 465 kg
Using the first law of motion, the acceleration (a) of the three-wheeler can be calculated as:
v = u + at
∴ a = v - u / t = 0-10/4 = -2.5 m/s2
The negative sign indicates that the velocity of the three-wheeler is decreasing with time.
Using Newton’s second law of motion, the net force acting on the three-wheeler can be calculated as:
F = Ma = 465 × (–2.5)
= –1162.5 N
The negative sign indicates that the force is acting against the direction of motion of the three-wheeler.
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