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Class 12
Physics
Magnetism and Matter
if the bar magnet in exercise 5 13 is turned aroun...

Question:
If the bar magnet in exercise 5.13 is turned around by 180º, wherewill the new null points be located?

Answer:

The magnetic field on the axis of the magnet at a distance d₁= 14 cm, can be written as:

Where, M = Magnetic moment

μ₀= Permeability of free space

H= Horizontal component of the magnetic field at d₁

If the bar magnet is turned through 180°, then the neutral point will lie on the equatorial line.

Hence, the magnetic field at a distance d₂, on the equatorial line of the magnet can be written as:

Equating equations (1) and (2), we get:

The new null points will be located 11.1 cm on the normal bisector.

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Question:
If the bar magnet in exercise 5.13 is turned around by 180º, wherewill the new null points be located?

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Question: If the bar magnet in exercise 5.13 is turned around by 180º, wherewill the new null points be located?

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Question:
If the bar magnet in exercise 5.13 is turned around by 180º, wherewill the new null points be located?