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Question:

If the bar magnet in exercise 5.13 is turned around by 180º, wherewill the new null points be located?

Answer:

The magnetic field on the axis of the magnet at a distance d1= 14 cm, can be written as:

Where, M = Magnetic moment

μ0= Permeability of free space

H= Horizontal component of the magnetic field at d1

If the bar magnet is turned through 180°, then the neutral point will lie on the equatorial line.

Hence, the magnetic field at a distance d2, on the equatorial line of the magnet can be written as:

Equating equations (1) and (2), we get:

The new null points will be located 11.1 cm on the normal bisector.


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