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a u shaped wire is dipped in a soap solution and...

Question:
A U-shaped wire is dipped in a soap solution, and removed. The thin soap film formed between the wire and the light slider supports a weight of 1.5 x 10^-2 N (which includes the small weight of the slider). The length of the slider is 30 cm. What is the surface tension of the film?

Answer:

The weight that the soap film supports, W = 1.5 × 10^-2 N

Length of the slider, l = 30 cm = 0.3 m

A soap film has two free surfaces.

∴Total length = 2l = 2 × 0.3 = 0.6 m

Surface tension, S = Force of Weight / 2l

= 1.5 × 10^-2 / 0.6 = 2.5 x 10^-2 N/m

Therefore, the surface tension of the film is 2.5 x 10^-2 N m^-1.

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Question:
A U-shaped wire is dipped in a soap solution, and removed. The thin soap film formed between the wire and the light slider supports a weight of 1.5 x 10^-2 N (which includes the small weight of the slider). The length of the slider is 30 cm. What is the surface tension of the film?

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Question: A U-shaped wire is dipped in a soap solution, and removed. The thin soap film formed between the wire and the light slider supports a weight of 1.5 x 10-2 N (which includes the small weight of the slider). The length of the slider is 30 cm. What is the surface tension of the film?

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Question:
A U-shaped wire is dipped in a soap solution, and removed. The thin soap film formed between the wire and the light slider supports a weight of 1.5 x 10^-2 N (which includes the small weight of the slider). The length of the slider is 30 cm. What is the surface tension of the film?