SELECT * FROM question_mgmt as q WHERE id=3343 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=2 AND subId=8 AND chapterId=103 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED)

Question:

A cricketer can throw a ball to a maximum horizontal distance of 100 m. How much high above the ground can the cricketer throw the same ball?

Answer:

Maximum horizontal distance, R = 100 m

The cricketer will only be able to throw the ball to the maximum horizontal distance when the angle of projection is 45°, i.e., θ = 45°.

The horizontal range for a projection velocity v, is given by the relation:

R  =  u2 sin2Ø / g

100  =  u2 / g  sin 90°

u2 / g   =  100            ....(i)

The ball will achieve the maximum height when it is thrown vertically upward. For such motion, the final velocity v is zero at the maximum height H.

Acceleration, a = –g

Using the third equation of motion:

v2  - u2  = -2gH

H  =  ½ x u2 / g  = ½ x 100 = 50m


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