SELECT * FROM question_mgmt as q WHERE id=3328 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=2 AND subId=8 AND chapterId=102 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED) CBSE Free NCERT Solution of 11th physics Motion in a straight Line figure 3 23 gives the x t plot of a particle execu

Question:

Figure 3.23 gives the x-t plot of a particle executing one-dimensional simple harmonic motion. (You will learn about this motion in more detail in Chapter14). Give the signs of position, velocity and acceleration variables of the particle at t = 0.3 s, 1.2 s, – 1.2 s.

                                       (Fig 3.23)

Answer:

Negative, Negative, Positive (at t = 0.3 s)

Positive, Positive, Negative (at t = 1.2 s)

Negative, Positive, Positive (at t = –1.2 s)

For simple harmonic motion (SHM) of a particle, acceleration (a) is given by the relation:

a = – ω2x ω → angular frequency …………..… (i)

t = 0.3 s

In this time interval, x is negative. Thus, the slope of the x-t plot will also be negative.

Therefore, both position and velocity are negative.

However, using equation (i), acceleration of the particle will be positive.

t = 1.2 s

In this time interval, x is positive.

Thus, the slope of the x-t plot will also be positive.

Therefore, both position and velocity are positive.

However, using equation (i), acceleration of the particle comes to be negative.

t = – 1.2 s

In this time interval, x is negative. Thus, the slope of the x-t plot will also be negative. Since both x and t are negative, the velocity comes to be positive. From equation (i), it can be inferred that the acceleration of the particle will be positive.


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SELECT ex_no,question,question_no,id,chapter FROM question_mgmt as q WHERE courseId='2' AND subId='8' AND ex_no!=0 AND status=1 and id!=3328 ORDER BY last_viewed_on desc limit 0,10

Comments

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  • 4 months ago

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  • Answered by Ekta Mehta
  • 4 months ago

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  • Answered by Ekta Mehta
  • 4 months ago

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