SELECT * FROM question_mgmt as q WHERE id=2260 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=3 AND subId=8 AND chapterId=118 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED)

Question:

A 3.0 cm wire carrying a current of 10 A is placed inside a solenoid perpendicular to its axis. The magnetic field inside the solenoid is given to be 0.27 T. What is the magnetic force on the wire?

Answer:

Length of the wire, l = 3 cm = 0.03 m

Current flowing in the wire, I = 10 A

Magnetic field, B = 0.27 T

Angle between the current and magnetic field, Ω¸ = 90°

Magnetic force exerted on the wire is given as:

F= BIlsinΩ¸

= 0.27 x 10 x 0.03 sin90°

= 8.1 x 10-2N

Hence, the magnetic force on the wire is 8.1 x 10-2 N. The direction of the force can be obtained from Fleming's left hand rule.


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