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Question:

For a CE-transistor amplifier, the audio signal voltage across the collected resistance of 2 kΩ is 2 V. Suppose the current amplification factor of the transistor is 100, find the input signal voltage and base current, if the base resistance is 1 kΩ.

Answer:

Collector resistance, R C = 2 kΩ = 2000 Ω

Audio signal voltage across the collector resistance, V = 2 V

Current amplification factor of the transistor, β = 100

Base resistance, R B = 1 kΩ = 1000 Ω

Input signal voltage = V i

Base current = I B

We have the amplification relation as: V/Vi = β Rc/Rb

Voltage amplification, Vi = V Rb / β Rc

= 2x1000 / 100x2000 = 0.01 V

Therefore, the input signal voltage of the amplifier is 0.01 V.

Base resistance is given by the relation: RB = Vi / IB

= 0.01 / 1000 = 10 μA

Therefore, the base current of the amplifier is 10 μA.


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