SELECT * FROM question_mgmt as q WHERE id=3274 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=2 AND subId=8 AND chapterId=101 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED) CBSE Free NCERT Solution of 11th physics Unit & measurment estimate the average mass density of a sodium atom

Question:

Estimate the average mass density of a sodium atom assuming its size to be about 2.5 Å. (Use the known values of Avogadro’s number and the atomic mass of sodium). Compare it with the density of sodium in its crystalline phase : 970 kg m–3. Are the two densities of the same order of magnitude ? If so, why ?

Answer:

Diameter of sodium atom = Size of sodium atom = 2.5 Å

Radius of sodium atom, r = 1/2 x 2.5 Å = 1.25 Å

= 1.25 × 10-10 m

Volume of sodium atom, V = 4/3 πr3

= 4/3 x 22/7 x (1.25 × 10-10) 3

According to the Avogadro hypothesis, one mole of sodium contains 6.023 × 1023 atoms and has a mass of 23 g or 23 × 10-3 kg.

∴ Mass of one atom = 23 × 10-3  / 6.023 x 10-3 kg

Density of sodium atom, p =

It is given that the density of sodium in crystalline phase is 970 kg m-3.

Hence, the density of sodium atom and the density of sodium in its crystalline phase are not in the same order. This is because in solid phase, atoms are closely packed. Thus, the inter-atomic separation is very small in the crystalline phase.


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