SELECT * FROM question_mgmt as q WHERE id=2747 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=3 AND subId=8 AND chapterId=124 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED) CBSE Free NCERT Solution of 12th physics Wave Optics in double slit experiment using light of wavelengt

Question:

In double-slit experiment using light of wavelength 600 nm, the angular width of a fringe formed on a distant screen is 0.1o. What is the spacing between the two slits?

Answer:

It is given that,

Wavelength of light used, λ = 6000 nm = 600 × 10 -9 m

Angular width of fringe, θ = 0.1° = 0.1 x ¶/180 = 3.14/1800 rad

Angular width of a fringe is related to slit spacing (d) as: d = λ/θ = 600 x 10-9/3.14/1800 = 3.44 x 10-4 m

Therefore, the spacing between the slits is 3.44 x 10 -4 m.


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SELECT ex_no,question,question_no,id,chapter FROM question_mgmt as q WHERE courseId='3' AND subId='8' AND ex_no!=0 AND status=1 and id!=2747 ORDER BY last_viewed_on desc limit 0,10

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  • Answered by Ekta Mehta
  • 4 months ago

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