SELECT * FROM question_mgmt as q WHERE id=3437 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=2 AND subId=8 AND chapterId=114 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED) CBSE Free NCERT Solution of 11th physics Waves a string of mass 2 50 kg is under a tension of 200

Question:

A string of mass 2.50 kg is under a tension of 200 N. The length of the stretched string is 20.0 m. If the transverse jerk is struck at one end of the string, how long does the disturbance take to reach the other end?

Answer:

Mass of the string, M = 2.50 kg

Tension in the string, T = 200 N

Length of the string, l = 20.0 m

Mass per unit length, μ = M / l = 2.50 / 20 = 0.125 kg m-1

The velocity (v) of the transverse wave in the string is given by the relation:

 v  =  underroot (T  / μ)

= Underroot (200 / 0.125) = 40 m/s

∴Time taken by the disturbance to reach the other end, t = l / v  =  20/40 = 0.50s


SELECT ex_no,question,question_no,id,chapter FROM question_mgmt as q WHERE courseId='2' AND subId='8' AND ex_no!=0 AND status=1 and id!=3437 ORDER BY views desc, last_viewed_on desc limit 0,10
SELECT ex_no,question,question_no,id,chapter FROM question_mgmt as q WHERE courseId='2' AND subId='8' AND ex_no!=0 AND status=1 and id!=3437 ORDER BY last_viewed_on desc limit 0,10

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  • 4 months ago

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