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Question:
A stone dropped from the top of a tower of height 300 m high splashes into the water of a pond near the base of the tower. When is the splash heard at the top given that the speed of sound in air is 340 m s^-1? (g= 9.8 m s^-2)

Answer:

Height of the tower, s = 300 m

Initial velocity of the stone, u = 0

Acceleration, a = g = 9.8 m/s²

Speed of sound in air = 340 m/s

The time (t₁) taken by the stone to strike the water in the pond can be calculated using the second equation of motion, as:

s = ut₁ + 1/2 gt²₁

300 = 0 + 1/2 x 9.8 x t12

∴ t₁= underroot [(300 x 2) / 9.8]

= 7.82 s

Time taken by the sound to reach the top of the tower, t₂ = 300/340 = 0.88 s

Therefore, the time after which the splash is heard, t = t₁ + t₂

= 7.82 + 0.88 = 8.7 s

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Question:
A stone dropped from the top of a tower of height 300 m high splashes into the water of a pond near the base of the tower. When is the splash heard at the top given that the speed of sound in air is 340 m s^-1? (g= 9.8 m s^-2)

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Question: A stone dropped from the top of a tower of height 300 m high splashes into the water of a pond near the base of the tower. When is the splash heard at the top given that the speed of sound in air is 340 m s-1? (g= 9.8 m s-2)

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Question:
A stone dropped from the top of a tower of height 300 m high splashes into the water of a pond near the base of the tower. When is the splash heard at the top given that the speed of sound in air is 340 m s^-1? (g= 9.8 m s^-2)