Express each number as a product of its | Class 10 Mathematics Chapter Real Numbers, Real Numbers NCERT Solutions

Question:

Express each number as a product of its prime factors:
   (i) 140     (ii) 156     (iii) 3825     (iv) 5005     (v) 7429

Answer:

(i) 140 

By taking the L.C.M of 140, we will get the product of its prime factors.
Therefore, 140 = 2 × 2 × 5 × 7 ×1 = 22
× 5 × 7

(ii) 156

By taking the L.C.M of 156, we will get the product of its prime factors.
Therefore, 156 = 2 ×  2 × 13 × 3 × 1 =  22
× 13 × 3

(iii) 3825

By taking the L.C.M of 3825, we will get the product of its prime factors.
Therefore, 3825 = 3 × 3 × 5 × 5 × 17 × 1 = 32
× 52 × 17 × 1

(iv) 5005 

By taking the L.C.M of 5005, we will get the product of its prime factors.
5005 = 5 × 5 × 11 × 13 × 1 = 5 × 7 × 11 × 1

(v) 7429 

By taking the L.C.M of 7429, we will get the product of its prime factors.
Therefore, 7429 = 17 × 19 × 13 × 1


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Welcome to the NCERT Solutions for Class 10 Mathematics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 2 , Question 1: Express each number as a product of its prime factors:    (i) 140     (ii)....