An aircraft executes a horizontal loop of radius 1.00 km with a steady speed of 900 km/h. Compare its centripetal acceleration with the acceleration due to gravity.
Radius of the loop, r = 1 km = 1000 m
Speed of the aircraft, v = 900 km/h = 900 x 5 /18 = 250 m/s
Centripetal acceleration, ac = v2 / r
= (250)2 / 1000 = 62.5 m/s2
Acceleration due to gravity, g = 9.8 m/s2
ac / g = 62.5 / 9.8 = 6.38
ac = 6.38g
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Welcome to the NCERT Solutions for Class 11 Physics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 18: An aircraft executes a horizontal loop of radius 1.00 km with a steady speed of 900 km/h. Compare it....
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