A wire stretched between two rigid suppo | Class 11 Physics Chapter Waves, Waves NCERT Solutions

Question:

A wire stretched between two rigid supports vibrates in its fundamental mode with a frequency of 45 Hz. The mass of the wire is 3.5 x 10-2 kg and its linear mass density is 4.0 x 10-2 kg m-1. What is

(a) the speed of a transverse wave on the string, and

(b) the tension in the string?

Answer:

(a) Mass of the wire, m = 3.5 × 10-2 kg

Linear mass density,  μ =  m / l =  4.0 x 10-2 kg m-1

Frequency of vibration, V = 45 Hz

∴Length of the wire,  l  = m / μ =    3.5 × 10-2  /  4.0 x 10-2

The wavelength of the stationary wave (λ) is related to the length of the wire by the relation:

λ = 2l / n

where , n = Number of nodes in the wire

For fundamental node, n = 1:

λ = 2l

λ = 2 × 0.875 = 1.75 m

The speed of the transverse wave in the string is given as:

v = V λ = 45 × 1.75 = 78.75 m/s

 

(b) The tension produced in the string is given by the relation:

T = v2 µ

= (78.75)2 × 4.0 × 10-2 = 248.06 N


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Welcome to the NCERT Solutions for Class 11 Physics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 14: A wire stretched between two rigid supports vibrates in its fundamental mode with a frequency of 45 ....