A pump on the ground floor of a building | Class 11 Physics Chapter Work Energy and Power, Work Energy and Power NCERT Solutions

Question:

A pump on the ground floor of a building can pump up water to fill a tank of volume 30 m3 in 15 min. If the tank is 40 m above the ground, and the efficiency of the pump is 30%, how much electric power is consumed by the pump?

Answer:

Volume of the tank, V= 30 m3

Time of operation, t = 15 min = 15 × 60 = 900 s

Height of the tank, h= 40 m

Efficiency of the pump, n = 30%

Density of water, p = 103 kg/m3

Mass of water, m= pV= 30 ×103 kg

Output power can be obtained as:

P0  =  work done / Time  =  mgh / t

 =  30 x 103 x 9.8 x 40  / 900  = 13.067 x 103 W

For input power Pi,, efficiency n is given by the relation:

n =  P0 / Pi  = 30%

Pi  =  13.067 / 30 x 100 x 103

= 43.6 kW


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Welcome to the NCERT Solutions for Class 11 Physics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 15: A pump on the ground floor of a building can pump up water to fill a tank of volume 30 m3 in 15 min.....