A pump on the ground floor of a building can pump up water to fill a tank of volume 30 m3 in 15 min. If the tank is 40 m above the ground, and the efficiency of the pump is 30%, how much electric power is consumed by the pump?
Volume of the tank, V= 30 m3
Time of operation, t = 15 min = 15 × 60 = 900 s
Height of the tank, h= 40 m
Efficiency of the pump, n = 30%
Density of water, p = 103 kg/m3
Mass of water, m= pV= 30 ×103 kg
Output power can be obtained as:
P0 = work done / Time = mgh / t
= 30 x 103 x 9.8 x 40 / 900 = 13.067 x 103 W
For input power Pi,, efficiency n is given by the relation:
n = P0 / Pi = 30%
Pi = 13.067 / 30 x 100 x 103
= 43.6 kW
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Welcome to the NCERT Solutions for Class 11 Physics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 15: A pump on the ground floor of a building can pump up water to fill a tank of volume 30 m3 in 15 min.....
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