A family uses 8 kW of power. (a) Direct solar energy is incident on the horizontal surface at an average rate of 200 W per square meter. If 20% of this energy can be converted to useful electrical energy, how large an area is needed to supply 8 kW? (b) Compare this area to that of the roof of a typical house.
(a) 200 m2
(a) Power used by the family, P = 8 kW = 8 × 103 W
Solar energy received per square metre = 200 W
Efficiency of conversion from solar to electricity energy = 20 %
Area required to generate the desired electricity = A
As per the information given in the question, we have:
8 x 103 = 20% x (A × 200)
= 20/100 x A x 200
∴ A = 8 x 103 / 40 = 200 m2
(b) The area of a solar plate required to generate 8 kW of electricity is almost equivalent to the area of the roof of a building having dimensions 14 m × 14 m.
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Welcome to the NCERT Solutions for Class 11 Physics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 23: A family uses 8 kW of power. (a) Direct solar energy is incident on the horizontal surface at an ave....
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