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  • A person trying to lose weight (dieter) lifts a 10 kg mass, one thousand times, to a height of 0.5 m each time. Assume that the potential energy lost each time she lowers the mass is dissipated. (a) How much work does she do against the gravitational force? (b) Fat supplies 3.8 x 107 J of energy per kilogram which is converted to mechanical energy with a 20% efficiency rate. How much fat will the dieter use up?

A person trying to lose weight (dieter) | Class 11 Physics Chapter Work Energy and Power, Work Energy and Power NCERT Solutions

Q22.

A person trying to lose weight (dieter) lifts a 10 kg mass, one thousand times, to a height of 0.5 m each time. Assume that the potential energy lost each time she lowers the mass is dissipated. (a) How much work does she do against the gravitational force? (b) Fat supplies 3.8 x 107 J of energy per kilogram which is converted to mechanical energy with a 20% efficiency rate. How much fat will the dieter use up?

(a) Mass of the weight, m = 10 kg

Height to which the person lifts the weight, h = 0.5 m

Number of times the weight is lifted, n = 1000

∴Work done against gravitational force:

= n(mgh)

= 1000 x 10 x 9.8 x 0.5

= 49 x 103J  = 49kJ

(b) Energy equivalent of 1 kg of fat = 3.8 × 107 J

Efficiency rate = 20%

Mechanical energy supplied by the person's body:

= 20/100 x 3.8 x 107 J

= 1/5 x 3.8 x 107 J

Equivalent mass of fat lost by the dieter:

= 1 / (1/5 x 3.8 x 107)  x 49 x 103

= 245 / 3.8 x 10-4

= 6.45 x 10-3 kg

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Important Questions & Answers

What is the correct answer to: A person trying to lose weight (dieter) lifts a 10 kg mass, one thousand times, to a height of 0.5 m each time. Assume that the potential energy lost each time she lowers the mass is dissipated. (a) How much work does she do against the gravitational force? (b) Fat supplies 3.8 x 107 J of energy per kilogram which is converted to mechanical energy with a 20% efficiency rate. How much fat will the dieter use up??

(a) Mass of the weight, m = 10 kg

Height to which the person lifts the weight, h = 0.5 m

Number of times the weight is lifted, n = 1000

∴Work done against gravitational force:

= n(mgh)

= 1000 x 10 x...

How do you solve A person trying to lose weight (dieter) lifts a 10 kg mass, one thousand times, to a height of 0.5 m each time. Assume that the potential energy lost each time she lowers the mass is dissipated. (a) How much work does she do against the gravitational force? (b) Fat supplies 3.8 x 107 J of energy per kilogram which is converted to mechanical energy with a 20% efficiency rate. How much fat will the dieter use up? step by step?

Step-by-step explanation:
• (a) Mass of the weight, m = 10 kg

• Height to which the person lifts the weight, h = 0
• 5 m

Why is this answer important for exams?

This question is important because it tests key concepts from the NCERT syllabus and is frequently asked in CBSE exams.

Which NCERT concept is used in this question?

This question is based on core NCERT concepts explained in the chapter and should be revised thoroughly before exams.

What common mistakes should be avoided in this question?

Students often lose marks by skipping steps, writing incomplete explanations, or misunderstanding keywords used in the question.

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